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Example 1
Input: logs = ["dig1 8 1 5 1","let1 art can","dig2 3 6","let2 own kit dig","let3 art zero"]
Output: ["let1 art can","let3 art zero","let2 own kit dig","dig1 8 1 5 1","dig2 3 6"]
Explanation:
The letter-log contents are all different, so their ordering is "art can", "art zero", "own kit dig".
The digit-logs have a relative order of "dig1 8 1 5 1", "dig2 3 6".
Example 2
Input: logs = ["a1 9 2 3 1","g1 act car","zo4 4 7","ab1 off key dog","a8 act zoo"]
Output: ["g1 act car","a8 act zoo","ab1 off key dog","a1 9 2 3 1","zo4 4 7"]
Code
class Solution:
def reorderLogFiles(self, logs: List[str]) -> List[str]:
letter, digit = [], []
for log in logs:
if log.split()[1].isdigit():
digit.append(log)
else:
letter.append(log)
letter.sort(key=lambda x : (x.split()[1:], x.split()[0]))
return letter + digit
출처 : https://leetcode.com/problems/reorder-data-in-log-files/submissions/
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